a business owner pays $1,200 per month in rent and a total of $120 per hour in employee salary for each hour…

a business owner pays $1,200 per month in rent and a total of $120 per hour in employee salary for each hour the store is open. on average, the store brings in $200 in net sales per hour. which equations can be solved to determine the break - even point if $c(x)$ represents the cost function, $r(x)$ represents the revenue function, and $x$ the number of hours per month the store is open?\n$c(x)=1,200 + 120x; r(x)=200x$\n$c(x)=1,200 + 120; r(x)=200x$\n$c(x)=200x; r(x)=1,200 + 120x$\n$c(x)=200x; r(x)=1,200 + 120$

a business owner pays $1,200 per month in rent and a total of $120 per hour in employee salary for each hour the store is open. on average, the store brings in $200 in net sales per hour. which equations can be solved to determine the break - even point if $c(x)$ represents the cost function, $r(x)$ represents the revenue function, and $x$ the number of hours per month the store is open?\n$c(x)=1,200 + 120x; r(x)=200x$\n$c(x)=1,200 + 120; r(x)=200x$\n$c(x)=200x; r(x)=1,200 + 120x$\n$c(x)=200x; r(x)=1,200 + 120$

Answer

Answer:

A. $C(x)=1200 + 120x; R(x)=200x$

Explanation:

Step1: Calcular el costo total

El alquiler es de $1200$ mensuales y el salario de empleados es de $120$ dólares por hora. Si $x$ es el número de horas que la tienda está abierta, el costo $C(x)$ es la suma del alquiler y el salario de empleados, es decir $C(x)=1200+120x$.

Step2: Calcular la recaudación total

La tienda tiene $200$ dólares en ventas netas por hora. Si $x$ es el número de horas que la tienda está abierta, la recaudación $R(x)$ es $R(x)=200x$.