destiny is going to start a planned savings to save up for a new car. she can afford to save 5% of her gross…

destiny is going to start a planned savings to save up for a new car. she can afford to save 5% of her gross income ($4,400) for this purpose. after 1 year of saving she decides to move the money into a certificate of deposit that pays 4.5% interest compounded monthly for an additional year. how much money should she have in the account at the end of the year (use the compound interest formula)?

destiny is going to start a planned savings to save up for a new car. she can afford to save 5% of her gross income ($4,400) for this purpose. after 1 year of saving she decides to move the money into a certificate of deposit that pays 4.5% interest compounded monthly for an additional year. how much money should she have in the account at the end of the year (use the compound interest formula)?

Answer

Explanation:

Step1: Calculate the annual savings

First, find out how much she saves in a year. Her gross income is $4400$ and she saves 5% of it. So the annual - savings $P$ is $P = 4400\times0.05\times12=4400\times0.6 = 2640$.

Step2: Identify the compound - interest formula variables

The compound - interest formula is $A=P(1 +\frac{r}{n})^{nt}$, where $P$ is the principal amount, $r$ is the annual interest rate (in decimal form), $n$ is the number of times interest is compounded per year, and $t$ is the number of years. Here, $P = 2640$, $r=0.045$ (since 4.5%=0.045), $n = 12$ (compounded monthly), and $t = 1$.

Step3: Calculate the amount in the account after one year of compounding

Substitute the values into the formula: [ \begin{align*} A&=2640(1+\frac{0.045}{12})^{12\times1}\ &=2640(1 + 0.00375)^{12}\ &=2640\times(1.00375)^{12} \end{align*} ] Using a calculator, $(1.00375)^{12}\approx1.04588$. Then $A = 2640\times1.04588\approx2761.28$.

Answer:

$2,761.28$