find the interest paid to the nearest cent for each loan balance, interest rate, and time.\n9. $800, 9%, 4…

find the interest paid to the nearest cent for each loan balance, interest rate, and time.\n9. $800, 9%, 4 years\n10. $280, 5.5%, 4 years\n11. $1,150, 7.6%, 5 years\n12. $266, 5.2%, 3 years\n13. $450, 22%, 1 year\n14. $2,180, 7.7%, 2 1/2 years\n15. $2,650, 3.65%, 4 1/2 years\n16. $1,245, 5.4%, 6 months\n461 mathematics: applications and concepts
Answer
Explanation:
Step1: Recall simple - interest formula
The simple - interest formula is $I = Prt$, where $I$ is the interest, $P$ is the principal amount, $r$ is the annual interest rate (in decimal form), and $t$ is the time in years.
Step2: Solve for problem 9
Given $P=$800$, $r = 9%=0.09$, and $t = 4$ years. $I=Prt=800\times0.09\times4 = 800\times0.36=$288.00$
Step3: Solve for problem 10
Given $P = $280$, $r=5.5% = 0.055$, and $t = 4$ years. $I=Prt=280\times0.055\times4=280\times0.22=$61.60$
Step4: Solve for problem 11
Given $P=$1150$, $r = 7.6%=0.076$, and $t = 5$ years. $I=Prt=1150\times0.076\times5=1150\times0.38=$437.00$
Step5: Solve for problem 12
Given $P=$266$, $r = 5.2%=0.052$, and $t = 3$ years. $I=Prt=266\times0.052\times3=266\times0.156=$41.496\approx$41.50$
Step6: Solve for problem 13
Given $P=$450$, $r = 22%=0.22$, and $t = 1$ year. $I=Prt=450\times0.22\times1=$99.00$
Step7: Solve for problem 14
Given $P=$2180$, $r = 7.7%=0.077$, and $t=2.5$ years. $I=Prt=2180\times0.077\times2.5=2180\times0.1925=$420.65$
Step8: Solve for problem 15
Given $P=$2650$, $r = 3.65%=0.0365$, and $t = 4.5$ years. $I=Prt=2650\times0.0365\times4.5=2650\times0.16425=$435.2625\approx$435.26$
Step9: Solve for problem 16
Given $P=$1245$, $r = 5.4%=0.054$, and $t = 6$ months $=0.5$ years. $I=Prt=1245\times0.054\times0.5=1245\times0.027=$33.615\approx$33.62$
Answer:
- $$288.00$
- $$61.60$
- $$437.00$
- $$41.50$
- $$99.00$
- $$420.65$
- $$435.26$
- $$33.62$