find the time required for an investment of 5000 dollars to grow to 8600 dollars at an interest rate of 7.5…

find the time required for an investment of 5000 dollars to grow to 8600 dollars at an interest rate of 7.5 percent per year, compounded quarterly.\n\nyour answer is $t = $ years.\nyou may enter the exact value or round to 2 decimal places.
Answer
Explanation:
Step1: Identify the compound interest formula
$$A = P \left(1 + \frac{r}{n}\right)^{nt}$$
Step2: List the given values
$A = 8600$, $P = 5000$, $r = 0.075$, $n = 4$
Step3: Substitute values into the formula
$$8600 = 5000 \left(1 + \frac{0.075}{4}\right)^{4t}$$
Step4: Simplify the equation
$$1.72 = (1.01875)^{4t}$$
Step5: Apply logarithms to solve for $t$
$$\ln(1.72) = 4t \ln(1.01875)$$
Step6: Isolate the variable $t$
$$t = \frac{\ln(1.72)}{4 \ln(1.01875)}$$
Step7: Calculate the final value
$$t \approx 7.31$$
Answer:
7.31