the interest earned on $7500 invested at 3.8% compounded monthly for 4 years would be $1229.11. false true…

the interest earned on $7500 invested at 3.8% compounded monthly for 4 years would be $1229.11. false true question 10 1 pts an amount of $2,535.00 is deposited in a bank paying an annual interest rate of 5.3 % compounded quarterly. find the balance after 3 years. $2,845 $2,000 $2,968.78 $29,687.8

the interest earned on $7500 invested at 3.8% compounded monthly for 4 years would be $1229.11. false true question 10 1 pts an amount of $2,535.00 is deposited in a bank paying an annual interest rate of 5.3 % compounded quarterly. find the balance after 3 years. $2,845 $2,000 $2,968.78 $29,687.8

Answer

Explanation:

Step1: Recall compound - interest formula

The compound - interest formula is (A = P(1+\frac{r}{n})^{nt}), where (P) is the principal amount, (r) is the annual interest rate (in decimal), (n) is the number of times interest is compounded per year, and (t) is the number of years. Given (P=$2535), (r = 5.3%=0.053), (n = 4) (compounded quarterly), and (t = 3) years.

Step2: Substitute values into the formula

First, calculate (\frac{r}{n}=\frac{0.053}{4}=0.01325) and (nt=4\times3 = 12). Then (A=2535\times(1 + 0.01325)^{12}). Calculate ((1 + 0.01325)^{12}\approx1.1711). So (A=2535\times1.1711\approx2968.78).

Answer:

($2,968.78)