investing $5,000 in a savings account at 2% annual interest compounded quarterly will result in…

investing $5,000 in a savings account at 2% annual interest compounded quarterly will result in approximately how much money after 10 years? use the formula $a = p(1+\frac{r}{n})^{nt}$ $5,361.61 $6,094.97 $6,103.97 $6,000.00

investing $5,000 in a savings account at 2% annual interest compounded quarterly will result in approximately how much money after 10 years? use the formula $a = p(1+\frac{r}{n})^{nt}$ $5,361.61 $6,094.97 $6,103.97 $6,000.00

Answer

Explanation:

Step1: Identify the values of $P$, $r$, $n$, and $t$

$P = 5000$, $r=0.02$, $n = 4$ (quarter - ly compounding), $t = 10$

Step2: Substitute the values into the compound - interest formula

$A=5000\left(1+\frac{0.02}{4}\right)^{4\times10}$

Step3: Simplify the expression inside the parentheses

$1+\frac{0.02}{4}=1 + 0.005=1.005$

Step4: Calculate the exponent

$4\times10 = 40$

Step5: Calculate the value of $(1.005)^{40}$

Using a calculator, $(1.005)^{40}\approx1.220794$

Step6: Calculate the value of $A$

$A = 5000\times1.220794=6103.97$

Answer:

C. $$6,103.97$