investment c: a bank account earns 5% per year, on average. how long will it take for an investment at this…

investment c: a bank account earns 5% per year, on average. how long will it take for an investment at this rate to double in price? 23/5 = 14.6 years how many times will an investment in it have doubled at this rate in 25 years? take the number of times an investment has doubled at this rate in 25 years and apply that to $1,000. what will that be worth? 5 years: 0 10 years: 0 15 years: 1 20 years: 1 25 years: 1
Answer
Explanation:
Step1: Recall compound - interest formula for doubling
The compound - interest formula for the future value of an investment is $A = P(1 + r)^t$, where $A$ is the future value, $P$ is the principal amount, $r$ is the annual interest rate, and $t$ is the number of years. When the investment doubles, $A = 2P$. So, $2P=P(1 + r)^t$. Canceling out $P$ (since $P\neq0$), we get $2=(1 + r)^t$.
Step2: Identify the interest rate
The annual interest rate $r = 0.05$ (since $5%=0.05$).
Step3: Solve for $t$
Take the natural logarithm of both sides of the equation $2=(1 + 0.05)^t$. We have $\ln(2)=\ln((1.05)^t)$. Using the property of logarithms $\ln(a^b)=b\ln(a)$, we get $\ln(2)=t\ln(1.05)$. Then $t=\frac{\ln(2)}{\ln(1.05)}\approx\frac{0.6931}{0.0488}\approx14.2$.
Answer:
It will take approximately 14.2 years for the investment to double.