jevonte invested $37,000 in an account paying an interest rate of 1.7% compounded quarterly. assuming no…

jevonte invested $37,000 in an account paying an interest rate of 1.7% compounded quarterly. assuming no deposits or withdrawals are made, how much money, to the nearest ten dollars, would be in the account after 14 years?
Answer
Explanation:
Step1: Identify the compound - interest formula
The compound - interest formula is $A = P(1+\frac{r}{n})^{nt}$, where $P$ is the principal amount, $r$ is the annual interest rate (in decimal form), $n$ is the number of times interest is compounded per year, and $t$ is the number of years.
Step2: Convert the given values to the correct form
$P=$37000$, $r = 0.017$ (since $1.7%=0.017$), $n = 4$ (compounded quarterly), and $t = 14$ years.
Step3: Substitute the values into the formula
$A=37000(1 +\frac{0.017}{4})^{4\times14}$ First, calculate the value inside the parentheses: $\frac{0.017}{4}=0.00425$, then $1+\frac{0.017}{4}=1 + 0.00425=1.00425$. Next, calculate the exponent: $4\times14 = 56$. So, $A = 37000\times(1.00425)^{56}$.
Step4: Calculate $(1.00425)^{56}$
Using a calculator, $(1.00425)^{56}\approx1.26177$.
Step5: Calculate the value of $A$
$A=37000\times1.26177 = 46685.49$. Rounding to the nearest ten dollars, $A\approx46690$.
Answer:
$46690$