lashonda has decided to invest to help with her retirement savings. how much would she have to invest to…

lashonda has decided to invest to help with her retirement savings. how much would she have to invest to have $136,900 after 16 years, assuming an interest rate of 3.56% compounded monthly? do not round any intermediate computations, and round your final answer to the nearest dollar. if necessary, refer to the list of financial formulas. your answer is incorrect. try again
Answer
Explanation:
Step1: Identify the compound - interest formula
The compound - interest formula for the future value $A$ is $A = P(1+\frac{r}{n})^{nt}$, where $A$ is the future value, $P$ is the principal amount (the initial investment we want to find), $r$ is the annual interest rate (as a decimal), $n$ is the number of times interest is compounded per year, and $t$ is the number of years. We are given that $A=$136900$, $r = 0.0356$ (since $3.56%=0.0356$), $n = 12$ (compounded monthly), and $t = 16$ years. We need to solve the formula for $P$: $P=\frac{A}{(1 +\frac{r}{n})^{nt}}$.
Step2: Substitute the values into the formula
First, calculate the exponent $nt$: $nt=12\times16 = 192$. Then, calculate $\frac{r}{n}$: $\frac{r}{n}=\frac{0.0356}{12}$. Next, calculate $(1+\frac{r}{n})^{nt}=(1 +\frac{0.0356}{12})^{192}$. $(1+\frac{0.0356}{12})\approx1+\ 0.002967=1.002967$. $(1.002967)^{192}\approx1.7997$. Finally, calculate $P$: $P=\frac{136900}{(1+\frac{0.0356}{12})^{192}}=\frac{136900}{1.7997}\approx76077$.
Answer:
$$76077$