malik opens a savings account with an initial...
malik opens a savings account with an initial deposit of $2500. the account earns 2.1% annual interest compounded quarterly. how much is in the account after 10 years? round to the nearest cent.
Answer
# Explanation:
## Step1: Identify compound - interest formula
The compound - interest formula is $A = P(1+\frac{r}{n})^{nt}$, where $A$ is the amount of money accumulated after $n$ years, including interest, $P$ is the principal amount (the initial amount of money), $r$ is the annual interest rate (in decimal form), $n$ is the number of times that interest is compounded per year, and $t$ is the time the money is invested for in years.
## Step2: Convert given values to appropriate form
We have $P = 2500$, $r=0.021$ (since $2.1\%=0.021$), $n = 4$ (compounded quarterly), and $t = 10$.
## Step3: Substitute values into the formula
$A=2500(1 +\frac{0.021}{4})^{4\times10}$.
First, calculate the value inside the parentheses: $\frac{0.021}{4}=0.00525$, and $1 + 0.00525=1.00525$.
Then, calculate the exponent: $4\times10 = 40$.
So, $A = 2500\times(1.00525)^{40}$.
## Step4: Calculate the final amount
Using a calculator, $(1.00525)^{40}\approx1.231439$.
Then, $A=2500\times1.231439 = 3078.5975$.
Rounding to the nearest cent, $A\approx3078.60$.
# Answer:
$3078.60$