micaela invested $1,400 in an account paying an interest rate of 3.6% compounded quarterly. assuming no…

micaela invested $1,400 in an account paying an interest rate of 3.6% compounded quarterly. assuming no deposits or withdrawals are made, how much money, to the nearest cent, would be in the account after 15 years?
Answer
Explanation:
Step1: Identify compound interest formula
The formula for compound interest is: $$A = P\left(1+\frac{r}{n}\right)^{nt}$$ Where:
- $A$ = final amount
- $P$ = principal amount
- $r$ = annual interest rate (decimal)
- $n$ = number of times compounded per year
- $t$ = time in years
Step2: Convert values to correct units
- $P = 1400$
- $r = \frac{3.6}{100} = 0.036$
- $n = 4$ (compounded quarterly)
- $t = 15$
Step3: Substitute values into formula
$$A = 1400\left(1+\frac{0.036}{4}\right)^{4 \times 15}$$
Step4: Simplify the expression
First calculate $\frac{0.036}{4}=0.009$, so $1+0.009=1.009$ Then calculate $4 \times 15=60$ $$A = 1400(1.009)^{60}$$
Step5: Calculate $(1.009)^{60}$
$(1.009)^{60} \approx 1.7137$
Step6: Compute final amount
$$A = 1400 \times 1.7137 \approx 2399.18$$
Answer:
$$2399.18$