a person invested $570 in an account growing at a rate allowing the money to double every 9 years. how much…

a person invested $570 in an account growing at a rate allowing the money to double every 9 years. how much money would be in the account after 29 years, to the nearest dollar?
Answer
Explanation:
Step1: Define doubling growth formula
The formula for exponential growth with doubling time is $A = P \times 2^{\frac{t}{d}}$, where $P$ is principal, $t$ is time, $d$ is doubling time.
Step2: Plug in given values
$P = 570$, $t = 29$, $d = 9$ $A = 570 \times 2^{\frac{29}{9}}$
Step3: Calculate exponent and growth factor
$\frac{29}{9} \approx 3.222$ $2^{3.222} \approx 2^{3} \times 2^{0.222} \approx 8 \times 1.1696 \approx 9.3568$
Step4: Compute final amount
$A \approx 570 \times 9.3568 \approx 5333.38$
Step5: Round to nearest dollar
Round $5333.38$ to the nearest whole number.
Answer:
$$5333$