the price that a company charged for a basketball hoop is given by the equation 50 - 5x² where x is the…

the price that a company charged for a basketball hoop is given by the equation 50 - 5x² where x is the number of hoops that are produced, in millions. it costs the company $30 to make each basketball hoop. the company recently reduced its production to 1 million hoops but maintained its profit of 15 million dollars. approximately how many basketball hoops did the company previously produce to make the same profit?\no 1.3 million hoops\no 1.4 million hoops\no 15 million hoops\no 30 million hoops
Answer
Explanation:
Step1: Define the profit - formula
Profit $P=(50 - 5x^{2}-30)x$. The selling - price per hoop is $50 - 5x^{2}$, the cost per hoop is $30$, and $x$ is the number of hoops in millions. Simplify the profit formula: $P=(20 - 5x^{2})x=20x-5x^{3}$.
Step2: Substitute the known values
We know that when $x = 1$ (1 million hoops), $P = 15$ million. We want to find $x$ when $P = 15$. So we set up the equation $15=20x-5x^{3}$, or $5x^{3}-20x + 15 = 0$. Divide through by $5$ to get $x^{3}-4x + 3 = 0$.
Step3: Factor the equation
We can factor $x^{3}-4x + 3$ as follows: $x^{3}-4x + 3=(x - 1)(x^{2}+x - 3)$. We already know $x = 1$ is one solution. To find the other non - 1 solution, we use the quadratic formula for $x^{2}+x - 3=0$. The quadratic formula for $ax^{2}+bx + c = 0$ is $x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. Here, $a = 1$, $b = 1$, and $c=-3$.
Step4: Apply the quadratic formula
$x=\frac{-1\pm\sqrt{1^{2}-4\times1\times(-3)}}{2\times1}=\frac{-1\pm\sqrt{1 + 12}}{2}=\frac{-1\pm\sqrt{13}}{2}$. We take the positive root since the number of hoops cannot be negative. $x=\frac{-1+\sqrt{13}}{2}\approx\frac{-1 + 3.606}{2}=\frac{2.606}{2}=1.303\approx1.3$.
Answer:
1.3 million hoops