the price that a company charged for a basketball hoop is given by the equation 50 - 5x² where x is the…

the price that a company charged for a basketball hoop is given by the equation 50 - 5x² where x is the number of hoops that are produced, in millions. it costs the company $30 to make each basketball hoop. the company recently reduced its production to 1 million hoops but maintained its profit of 15 million dollars. approximately how many basketball hoops did the company previously produce to make the same profit?\n1.3 million hoops\n1.4 million hoops\n15 million hoops\n30 million hoops

the price that a company charged for a basketball hoop is given by the equation 50 - 5x² where x is the number of hoops that are produced, in millions. it costs the company $30 to make each basketball hoop. the company recently reduced its production to 1 million hoops but maintained its profit of 15 million dollars. approximately how many basketball hoops did the company previously produce to make the same profit?\n1.3 million hoops\n1.4 million hoops\n15 million hoops\n30 million hoops

Answer

Explanation:

Step1: Define the profit formula

Profit $P=(50 - 5x^{2}-30)x$. The selling - price per hoop is $50 - 5x^{2}$, the cost per hoop is $30$, and $x$ is the number of hoops in millions. So, $P=(20 - 5x^{2})x=20x-5x^{3}$.

Step2: Find the value of $x$ when current production is 1 million

When $x = 1$ million, $P=(20\times1-5\times1^{3})=15$ million dollars.

Step3: Set up the equation for the previous production

We want to find $x$ such that $20x-5x^{3}=15$. Rearrange the equation to get $5x^{3}-20x + 15 = 0$. Divide through by 5: $x^{3}-4x + 3=0$.

Step4: Factor the equation

We can factor $x^{3}-4x + 3$ as $(x - 1)(x^{2}+x - 3)=0$. We already know $x = 1$ is a solution (the current production). For the quadratic factor $x^{2}+x - 3=0$, use the quadratic formula $x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ with $a = 1$, $b = 1$, and $c=-3$. $x=\frac{-1\pm\sqrt{1^{2}-4\times1\times(-3)}}{2\times1}=\frac{-1\pm\sqrt{1 + 12}}{2}=\frac{-1\pm\sqrt{13}}{2}$. We take the positive root since $x$ (number of hoops) cannot be negative. $x=\frac{-1+\sqrt{13}}{2}\approx\frac{-1 + 3.606}{2}\approx1.3$ million hoops.

Answer:

1.3 million hoops