question 11\nfind the final amount of money in an account if $600 is deposited at 2% interest compounded…

Explanation:

Step1: Identify compound - interest formula

The compound - interest formula is $A = P(1+\frac{r}{n})^{nt}$, where $A$ is the final amount, $P$ is the principal amount, $r$ is the annual interest rate (in decimal), $n$ is the number of times interest is compounded per year, and $t$ is the number of years.

Step2: Convert values to appropriate form

Given $P = 600$, $r=0.02$ (since $2%=0.02$), $n = 52$ (compounded weekly), and $t = 9$.

Step3: Substitute values into the formula

$A=600(1 +\frac{0.02}{52})^{52\times9}$. First, calculate the value inside the parentheses: $\frac{0.02}{52}\approx0.000384615$, then $1+\frac{0.02}{52}=1 + 0.000384615=1.000384615$. Next, calculate the exponent: $52\times9 = 468$. So, $A = 600\times(1.000384615)^{468}$. $(1.000384615)^{468}\approx1.197297$. Then $A=600\times1.197297 = 718.3782$.

Step4: Round the answer

Rounding $718.3782$ to 2 decimal places, we get $A\approx718.38$.

Answer:

$718.38$