question 7\na bank loaned out $21,500, part of it at the rate of 10% annual interest, and the rest at 2%…

question 7\na bank loaned out $21,500, part of it at the rate of 10% annual interest, and the rest at 2% annual interest. the total interest earned for both loans was $1,270.00. how much was loaned at each rate?\n$ was loaned at 10% and\n$ was loaned at 2%.\nquestion help: video message instructor post to forum
Answer
Explanation:
Step1: Let the amount loaned at 10% be $x$.
Then the amount loaned at 2% is $(21500 - x)$.
Step2: Calculate the interest from each loan.
The interest from the 10% - loan is $0.1x$, and the interest from the 2% - loan is $0.02(21500 - x)$.
Step3: Set up the equation based on the total - interest.
$0.1x+0.02(21500 - x)=1270$.
Step4: Expand and simplify the equation.
$0.1x + 430-0.02x=1270$. Combining like - terms gives $0.1x-0.02x=1270 - 430$. $0.08x=840$.
Step5: Solve for $x$.
$x=\frac{840}{0.08}=10500$.
Step6: Find the amount loaned at 2%.
The amount loaned at 2% is $21500 - 10500 = 11000$.
Answer:
$10500$ was loaned at 10% and $11000$ was loaned at 2%.