rachel starts an ira (individual retirement account) at the age of 22 to save for retirement. she deposits…

rachel starts an ira (individual retirement account) at the age of 22 to save for retirement. she deposits $300 each month. the ira has an average annual interest rate of 8% compounded monthly. how much money will she have saved when she retires at the age of 65? round your answer to the nearest cent; if necessary.

rachel starts an ira (individual retirement account) at the age of 22 to save for retirement. she deposits $300 each month. the ira has an average annual interest rate of 8% compounded monthly. how much money will she have saved when she retires at the age of 65? round your answer to the nearest cent; if necessary.

Answer

Answer:

$1,398,857.82$

Explanation:

Step1: Calculate the number of months

Rachel starts at 22 and retires at 65. The number of years is $65 - 22=43$ years. The number of months $n = 43\times12 = 516$ months.

Step2: Calculate the monthly interest rate

The annual interest rate $r = 8%=0.08$. The monthly interest rate $i=\frac{0.08}{12}$

Step3: Use the future - value of an ordinary annuity formula

The formula for the future value of an ordinary annuity is $F = A\times\frac{(1 + i)^{n}-1}{i}$, where $A = 300$. Substitute $A = 300$, $i=\frac{0.08}{12}$, and $n = 516$ into the formula: [ \begin{align*} F&=300\times\frac{(1+\frac{0.08}{12})^{516}-1}{\frac{0.08}{12}}\ \end{align*} ] First, calculate $(1+\frac{0.08}{12})^{516}$. Let $x=\frac{0.08}{12}\approx0.00667$. Then $(1 + x)^{n}=(1.00667)^{516}$. Using a calculator, $(1.00667)^{516}\approx4.6636$ [ \begin{align*} (1.00667)^{516}-1&\approx4.6636- 1=3.6636\ \frac{(1.00667)^{516}-1}{\frac{0.08}{12}}&=\frac{3.6636}{\frac{0.08}{12}}=\frac{3.6636\times12}{0.08}\ &=\frac{43.9632}{0.08}=549.54\ F&=300\times549.54 = 1398857.82 \end{align*} ]