3 suppose an investment of $6,200 doubles in value every 13 years. how much is the investment worth after 78…

3 suppose an investment of $6,200 doubles in value every 13 years. how much is the investment worth after 78 years? $74,400 $161,200 $396,800 $967,200

3 suppose an investment of $6,200 doubles in value every 13 years. how much is the investment worth after 78 years? $74,400 $161,200 $396,800 $967,200

Answer

Explanation:

Step1: Calcular el número de períodos

Dividir el número total de años (78) entre la duración de cada período (13 años). $n=\frac{78}{13}=6$

Step2: Calcular el valor final del investimiento

El valor inicial del investimiento es $6200 y se duplica en cada período. Utilizar la fórmula $A = P\times2^{n}$, donde $P = 6200$ y $n = 6$. $A=6200\times2^{6}$ $A = 6200\times64$ $A=396800$

Answer:

$396800$ (la opción correcta es la tercera opción en la lista que se presenta en la imagen: $396800$)