what is the value of $sqrt{16}$?

# Explanation: ## Step1: Recall square - root definition The square - root of a number \(x\), \(\sqrt{x}\), is a value \(y\) such that \(y^2=x\). We need to find a number \(y\) where \(y^2 = 16\). ## Step2: Find the number We know that \(4\times4 = 16\) and \((- 4)\times(-4)=16\). But when we write \(\sqrt{16}\), by convention, we mean the principal (non - negative) square root. So \(\sqrt{16}=4\). # Answer: 4