1. a 100 - ft steel tape known to be only 99.98 ft long (under standard conditions) was used to record a…

1. a 100 - ft steel tape known to be only 99.98 ft long (under standard conditions) was used to record a measurement of 276.22 ft. what is the distance corrected for the erroneous tape?\n2. it is required to lay out a rectangular commercial building 200.00 ft wide and 350.00 ft long. if the steel tape being used is 100.02 ft long (under standard conditions), what distance should be laid out?

1. a 100 - ft steel tape known to be only 99.98 ft long (under standard conditions) was used to record a measurement of 276.22 ft. what is the distance corrected for the erroneous tape?\n2. it is required to lay out a rectangular commercial building 200.00 ft wide and 350.00 ft long. if the steel tape being used is 100.02 ft long (under standard conditions), what distance should be laid out?

Answer

Explanation:

Step1: Determine the tape - error ratio

The actual length of the tape is $L_{actual}=100.02$ ft and the nominal length is $L_{nominal} = 100$ ft. The ratio of the actual length to the nominal length is $r=\frac{L_{actual}}{L_{nominal}}=\frac{100.02}{100}=1.0002$.

Step2: Calculate the corrected distance

The measured distance is $d_{measured}=276.22$ ft. The corrected distance $d_{corrected}$ is found by multiplying the measured distance by the ratio $r$. So, $d_{corrected}=d_{measured}\times r = 276.22\times1.0002=276.275244$ ft.

Answer:

$276.28$ ft (rounded to two decimal places)