what answer should be reported, with the correct number of significant figures, for the following…

what answer should be reported, with the correct number of significant figures, for the following calculation? (249.362 + 41)/63.498\n4.573\n4.6\n4.5728\n4.57277\n4.57\nquestion 35\n1 pts\nround the following number to four significant figures and express the result in standard exponential notation: 25.6623×10^5\n0.2566×10^3\n0.2566×10^7\n2.566×10^4\n25.66×10^5\n2.566×10^6

what answer should be reported, with the correct number of significant figures, for the following calculation? (249.362 + 41)/63.498\n4.573\n4.6\n4.5728\n4.57277\n4.57\nquestion 35\n1 pts\nround the following number to four significant figures and express the result in standard exponential notation: 25.6623×10^5\n0.2566×10^3\n0.2566×10^7\n2.566×10^4\n25.66×10^5\n2.566×10^6

Answer

Question 1

Explanation:

Step1: Calculate the sum in the numerator

$249.362 + 41=290.362$

Step2: Perform the division

$\frac{290.362}{63.498}\approx4.57277$

Step3: Determine significant - figures

The least number of significant figures in the values used in the calculation ($249.362$ has 6 significant figures, $41$ has 2 significant figures, and $63.498$ has 5 significant figures) is 2. So, we round the result to 2 significant figures. Rounding $4.57277$ to 2 significant figures gives $4.6$.

Answer:

4.6

Question 2

Explanation:

First, round the coefficient $25.6623$ to four significant figures. Rounding $25.6623$ to four significant figures gives $25.66$. Then, express it in standard exponential notation. The original number is $25.6623\times 10^{5}$. When we round the coefficient and keep the scientific - notation form, we get $2.566\times 10^{6}$ (since $25.66 = 2.566\times10^{1}$ and when multiplied by $10^{5}$, we use the rule of exponents $a^{m}\times a^{n}=a^{m + n}$, so $2.566\times10^{1}\times10^{5}=2.566\times 10^{6}$).

Answer:

$2.566\times 10^{6}$