calculate the weight of the piece of steel shown in the drawing. (this steel weighs 0.283 lb/in.³) the…

calculate the weight of the piece of steel shown in the drawing. (this steel weighs 0.283 lb/in.³) the weight of the piece of steel shown in the drawing is approximately lb. (round to the nearest tenth as needed.)

calculate the weight of the piece of steel shown in the drawing. (this steel weighs 0.283 lb/in.³) the weight of the piece of steel shown in the drawing is approximately lb. (round to the nearest tenth as needed.)

Answer

Explanation:

Step1: Calculate radius of base

The diameter of the base is $2.35$ inches, so the radius $r=\frac{2.35}{2}=1.175$ inches.

Step2: Calculate volume of cylinder

The formula for the volume of a cylinder is $V_{cylinder}=\pi r^{2}h$. Here, $h = 4.5$ inches. So $V_{cylinder}=\pi\times(1.175)^{2}\times4.5\approx\pi\times1.380625\times4.5\approx19.57$ in³.

Step3: Calculate volume of cone

The formula for the volume of a cone is $V_{cone}=\frac{1}{3}\pi r^{2}h$. Here, $h = 1.5$ inches. So $V_{cone}=\frac{1}{3}\pi\times(1.175)^{2}\times1.5=\pi\times1.380625\times0.5\approx2.17$ in³.

Step4: Calculate total volume

$V = V_{cylinder}+V_{cone}\approx19.57 + 2.17=21.74$ in³.

Step5: Calculate weight

The weight $W$ is given by the density times the volume. The density is $0.283$ lb/in³. So $W=0.283\times21.74\approx6.2$ lb.

Answer:

$6.2$