cfa 3/21\n1) the width of a rectangle is 4 feet, and the diagonal length of the rectangle is 13 feet. which…

cfa 3/21\n1) the width of a rectangle is 4 feet, and the diagonal length of the rectangle is 13 feet. which measurement is closest to the length of this rectangle in feet?\nf 9 ft\ng 17 ft\nh 12.4 ft\nj 13.6 ft\n2) the density of oxygen is 0.001429 grams per cubic centimeter. how is this number written in scientific notation?

cfa 3/21\n1) the width of a rectangle is 4 feet, and the diagonal length of the rectangle is 13 feet. which measurement is closest to the length of this rectangle in feet?\nf 9 ft\ng 17 ft\nh 12.4 ft\nj 13.6 ft\n2) the density of oxygen is 0.001429 grams per cubic centimeter. how is this number written in scientific notation?

Answer

Explanation:

Step1: Apply Pythagorean theorem

Let the width $w = 4$ feet, the diagonal $d=13$ feet, and the length $l$. According to the Pythagorean theorem $l^{2}+w^{2}=d^{2}$, so $l=\sqrt{d^{2}-w^{2}}$.

Step2: Substitute values

Substitute $w = 4$ and $d = 13$ into the formula: $l=\sqrt{13^{2}-4^{2}}=\sqrt{169 - 16}=\sqrt{153}$.

Step3: Calculate the square - root

$\sqrt{153}\approx12.369\approx12.4$ feet.

Answer:

H. 12.4 ft