1. complete the following table. provide a full solution of your calculations in the space provided.\n2…

Explanation:

Step1: Convert hexadecimal 4D3 to decimal and binary

• First, convert hexadecimal to decimal. In hexadecimal, (4D3_{16}=4\times16^{2}+13\times16^{1}+3\times16^{0}) (since (D = 13) in decimal). [4\times16^{2}+13\times16^{1}+3\times16^{0}=4\times256 + 13\times16+3\times1=1024+208 + 3=1235_{10}]
• Then, convert decimal 1235 to binary. Divide 1235 by 2 successively: [1235\div2 = 617\cdots1] [617\div2=308\cdots1] [308\div2 = 154\cdots0] [154\div2=77\cdots0] [77\div2 = 38\cdots1] [38\div2=19\cdots0] [19\div2 = 9\cdots1] [9\div2=4\cdots1] [4\div2 = 2\cdots0] [2\div2=1\cdots0] [1\div2 = 0\cdots1] Reading the remainders from bottom - to - top, (1235_{10}=10011000011_{2})

Step2: Convert binary 11011101 to decimal and hexadecimal

• Convert binary to decimal: (11011101_{2}=1\times2^{7}+1\times2^{6}+0\times2^{5}+1\times2^{4}+1\times2^{3}+1\times2^{2}+0\times2^{1}+1\times2^{0}) [=128 + 64+0 + 16+8 + 4+0 + 1=221_{10}]
• Convert decimal 221 to hexadecimal. Divide 221 by 16: [221\div16 = 13\cdots13] (13 is D in hexadecimal) [13\div16=0\cdots13] (13 is D in hexadecimal) So (221_{10}=DD_{16})

Step3: Convert decimal 64 to binary and hexadecimal

• Convert decimal to binary. Divide 64 by 2 successively: [64\div2 = 32\cdots0] [32\div2=16\cdots0] [16\div2 = 8\cdots0] [8\div2=4\cdots0] [4\div2 = 2\cdots0] [2\div2=1\cdots0] [1\div2 = 0\cdots1] Reading the remainders from bottom - to - top, (64_{10}=1000000_{2})
• Convert decimal 64 to hexadecimal. Divide 64 by 16: [64\div16 = 4\cdots0] So (64_{10}=40_{16})

Answer:

Decimal	Binary	Hexadecimal
1235	10011000011	4D3
221	11011101	DD
64	1000000	40