create the following. assign the part the material \400 series stainless steel\. what is the mass of the…

Explanation:

Step1: Calculate volume of rectangular - part

The rectangular part has length $l = 100$ mm, width $w=60$ mm and depth $d = 25$ mm. The volume of the rectangular - part $V_{rect}=l\times w\times d=100\times60\times25 = 150000$ $mm^{3}$.

Step2: Calculate volume of circular - hole

The circular hole has diameter $D = 45$ mm, so radius $r=\frac{D}{2}=22.5$ mm. The volume of the circular - hole $V_{hole}=\pi r^{2}d=\pi\times(22.5)^{2}\times25\approx\pi\times506.25\times25\approx39760.78$ $mm^{3}$.

Step3: Calculate net volume of the part

$V = V_{rect}-V_{hole}=150000 - 39760.78=110239.22$ $mm^{3}$. Convert to $m^{3}$: $V=110239.22\times10^{-9}$ $m^{3}$.

Step4: Find density of 400 - Series Stainless Steel

The density of 400 - Series Stainless Steel $\rho\approx7.7\times10^{3}$ $kg/m^{3}$.

Step5: Calculate mass of the part

Using the formula $m=\rho V$, we have $m = 7.7\times10^{3}\times110239.22\times10^{-9}\approx0.849842$ kg $\approx0.851$ kg.

Answer:

0.851 kg