the decimal number 15 would be written in binary as: a 1111. b 1000. c 4c. d 00011001.
the decimal number 15 would be written in binary as: a 1111. b 1000. c 4c. d 00011001.
Answer
Explanation:
Step1: Divide by 2 and get remainders
$15\div2 = 7$ remainder $1$ $7\div2=3$ remainder $1$ $3\div2 = 1$ remainder $1$ $1\div2=0$ remainder $1$
Step2: Read remainders in reverse - order
Reading the remainders from bottom - to - top gives 1111.
Answer:
A. 1111