this hydraulic lift is designed to lift a 3,000 - pound car. the diameter of the cylinder under the car at…

this hydraulic lift is designed to lift a 3,000 - pound car. the diameter of the cylinder under the car at piston 2 is 3 feet. the diameter of the cylinder at piston 1 is 6 inches. what is the area in square feet (ft²) of the circular surface of each piston? use 3.14 for π. a₁ = 7 ft²; a₂ = 0.2 ft² a₁ = 0.8 ft²; a₂ = 28 ft² a₁ = 0.2 ft²; a₂ = 7 ft² a₁ = 28 ft²; a₂ = 7 ft²
Answer
Explanation:
Step1: Convert diameter of Piston 1 to feet
1 inch = $\frac{1}{12}$ feet, so 6 inches = $6\times\frac{1}{12}=0.5$ feet.
Step2: Calculate area of Piston 1
The area formula for a circle is $A = \pi r^{2}$, where $r$ is the radius. For Piston 1, $r_1=\frac{d_1}{2}=\frac{0.5}{2}=0.25$ feet. Then $A_1=\pi r_1^{2}=3.14\times(0.25)^{2}=3.14\times0.0625 = 0.19625\approx0.2$ $ft^{2}$.
Step3: Calculate area of Piston 2
For Piston 2, $d_2 = 3$ feet, $r_2=\frac{d_2}{2}=\frac{3}{2}=1.5$ feet. Then $A_2=\pi r_2^{2}=3.14\times(1.5)^{2}=3.14\times2.25 = 7.065\approx7$ $ft^{2}$.
Answer:
$A_1 = 0.2$ $ft^{2}$; $A_2 = 7$ $ft^{2}$