for each multiple choice question, choose the best answer. for each short answer question, type your…

for each multiple choice question, choose the best answer. for each short answer question, type your responses in appropriate box numbers below the questions. question 10 (3 points) answer the following logarithmic application questions related to sciences (write final answers only). #1) what is the ph of a solution with a hydrogen - ion concentration of 3.7×10^(-3) mol/l? #2) how many times more intense is an earthquake measuring 8 on the richter scale than one measuring 5 on the richter scale? #3) how many times more intense is the sound of a rock concert (150 db) when compared to a normal conversation (60 db)? blank #1 2.43 blank #2 blank #3
Answer
Explanation:
Step1: Recall pH formula
The formula for pH is $pH = -\log[H^+]$, where $[H^+]$ is the hydrogen - ion concentration. Given $[H^+]=3.7\times 10^{-3}\ mol/L$. Then $pH = -\log(3.7\times 10^{-3})$. Using the logarithm property $\log(ab)=\log a+\log b$, we have $pH=-(\log3.7+\log(10^{-3}))$. Since $\log(10^{-3})=- 3$ and $\log3.7\approx0.57$, then $pH=- (0.57 - 3)=2.43$.
Step2: Recall Richter - scale formula
The Richter - scale formula is $M=\log\left(\frac{I}{I_0}\right)$, where $M$ is the magnitude, $I$ is the intensity of the earthquake, and $I_0$ is a reference intensity. For an earthquake of magnitude $M_1 = 8$, $\log\left(\frac{I_1}{I_0}\right)=8$, so $\frac{I_1}{I_0}=10^8$. For an earthquake of magnitude $M_2 = 5$, $\log\left(\frac{I_2}{I_0}\right)=5$, so $\frac{I_2}{I_0}=10^5$. The ratio of intensities $\frac{I_1}{I_2}=\frac{10^8}{10^5}=10^{8 - 5}=1000$.
Step3: Recall decibel formula
The decibel formula is $dB = 10\log\left(\frac{I}{I_0}\right)$. For a rock concert with $dB_1 = 150$, $150 = 10\log\left(\frac{I_1}{I_0}\right)$, so $\log\left(\frac{I_1}{I_0}\right)=15$ and $\frac{I_1}{I_0}=10^{15}$. For a normal conversation with $dB_2 = 60$, $60 = 10\log\left(\frac{I_2}{I_0}\right)$, so $\log\left(\frac{I_2}{I_0}\right)=6$ and $\frac{I_2}{I_0}=10^{6}$. The ratio of intensities $\frac{I_1}{I_2}=\frac{10^{15}}{10^{6}}=10^{15 - 6}=10^9$.
Answer:
Blank #1: 2.43 Blank #2: 1000 Blank #3: $10^9$