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# Explanation: ## Step1: Identify the hypotheses Let $p$ be the proportion of business - students who have personal computers at home. The null hypothesis $H_0:p = 0.25$ and the alternative hypothesis $H_1:p>0.25$ (since if the proportion exceeds 25%, the lab will scale back the proposed enlargement). ## Step2: Calculate the test - statistic for a proportion The test - statistic for a proportion is $z=\frac{\hat{p}-p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}}$, where $\hat{p}=\frac{x}{n}$, $x = 65$ is the number of successes, $n = 200$ is the sample size, and $p_0=0.25$. But we are asked to find the rejection region, not the test - statistic value. ## Step3: Determine the critical value Since $\alpha = 0.01$ and the test is a right - tailed test (because $H_1:p>0.25$), we look up the $z$ - value in the standard normal distribution table. The critical $z$ - value $z_{\alpha}$ for a right - tailed test with $\alpha=0.01$ is such that $P(Z>z_{\alpha})=\alpha$. From the standard normal table, $z_{0.01}=2.33$. ## Step4: Define the rejection region For a right - tailed test, the rejection region is $z>z_{\alpha}$. So the rejection region is $z > 2.33$. # Answer: B. Reject $H_0$ if $z>2.33$