question 10 (1 point)\nchopping wood burns about 400. cal/h and a serving of garbonzo beans contains 105.5…

question 10 (1 point)\nchopping wood burns about 400. cal/h and a serving of garbonzo beans contains 105.5 cal. how long would you have to chop wood in order to burn off the beans ?\n(105.5 cal)(400. cal/h) = 42,000 h\n(105.5 cal(1 h/400. cal) = 0.264 h\nchopping wood is too dangerous

question 10 (1 point)\nchopping wood burns about 400. cal/h and a serving of garbonzo beans contains 105.5 cal. how long would you have to chop wood in order to burn off the beans ?\n(105.5 cal)(400. cal/h) = 42,000 h\n(105.5 cal(1 h/400. cal) = 0.264 h\nchopping wood is too dangerous

Answer

Explanation:

Step1: Identify the relationship

We know the calorie - burn rate of chopping wood and the calorie content of beans. We use the formula $t=\frac{C_{beans}}{C_{rate}}$, where $t$ is the time, $C_{beans}$ is the calorie content of beans, and $C_{rate}$ is the calorie - burn rate of chopping wood.

Step2: Substitute the values

$C_{beans} = 105.5$ CAL and $C_{rate}=400$ CAL/h. So $t=\frac{105.5\text{ CAL}}{400\text{ CAL/h}}$.

Step3: Calculate the time

$t = 105.5\times\frac{1\text{ h}}{400}=0.264$ h

Answer:

$(105.5\text{ CAL})(1\text{ h}/400\text{ CAL}) = 0.264$ h