question 18\ncomputers the byte is the fundamental unit of computer processing. almost all aspects of a…

question 18\ncomputers the byte is the fundamental unit of computer processing. almost all aspects of a computers performance and specifications are measured in bytes or multiples of bytes. the byte is based on powers of 2, as shown in the table. how many times greater is a megabyte than a kilobyte?\n| memory term | number of bytes |\n| ---- | ---- |\n| kilobyte | $2^{10}$ |\n| megabyte | $2^{20}$ |\n| gigabyte | $2^{30}$ |\na) $2^{20}=1,048,576$\nb) $2^{10}=1024$\nc) $2^{30}=1,073,741,824$\nd) $2^{0}=1$

question 18\ncomputers the byte is the fundamental unit of computer processing. almost all aspects of a computers performance and specifications are measured in bytes or multiples of bytes. the byte is based on powers of 2, as shown in the table. how many times greater is a megabyte than a kilobyte?\n| memory term | number of bytes |\n| ---- | ---- |\n| kilobyte | $2^{10}$ |\n| megabyte | $2^{20}$ |\n| gigabyte | $2^{30}$ |\na) $2^{20}=1,048,576$\nb) $2^{10}=1024$\nc) $2^{30}=1,073,741,824$\nd) $2^{0}=1$

Answer

Explanation:

Step1: Recall the formula for ratio

To find how many times greater a megabyte is than a kilobyte, we divide the number of bytes in a megabyte by the number of bytes in a kilobyte.

Step2: Identify the number of bytes

Number of bytes in a megabyte is $2^{20}$, and in a kilobyte is $2^{10}$.

Step3: Calculate the ratio

Using the rule of exponents $\frac{a^m}{a^n}=a^{m - n}$, we have $\frac{2^{20}}{2^{10}}=2^{20 - 10}=2^{10}$.

Answer:

B. $2^{10}=1024$