question 19 (4 points)\nhow many mg in 9.900 x 10^(-6) tg? note, this is set up as a two - step…

question 19 (4 points)\nhow many mg in 9.900 x 10^(-6) tg? note, this is set up as a two - step problem.\nthe intermediate answer is numerically __1__ and the units are __2__.\nthe final answer is numerically __3__ and the units are __4__.\na. 9.900 x 10^(-6) b. 9.900 x 10^6 c. 9.900 x 10^(-12) d. 9.900 x 10^12\ne. 9.900 x 10^0 f. 9.900 x 10^(-9) g. 9.900 x 10^9 h. 9.900 x 10^(-3)\ni. 9.900 x 10^3 j. g k. mg l. tg m. no units
Answer
Explanation:
Step1: Convert Tg to g
We know that $1\ Tg = 10^{12}\ g$. So for $9.900\times 10^{-6}\ Tg$, we have $9.900\times 10^{-6}\times10^{12}\ g=9.900\times 10^{6}\ g$. The intermediate - answer numerically is $9.900\times 10^{6}$ and the units are $g$.
Step2: Convert g to Mg
We know that $1\ Mg = 10^{6}\ g$. So, $\frac{9.900\times 10^{6}\ g}{10^{6}\ g/Mg}=9.900\times 10^{0}\ Mg$. The final answer numerically is $9.900\times 10^{0}$ and the units are $Mg$.
Answer:
- B. $9.900\times 10^{6}$
- J. g
- E. $9.900\times 10^{0}$
- K. Mg