question 8 of 24\nlook at the table below. rewrite the mass for the third object in scientific notation.\n|…

question 8 of 24\nlook at the table below. rewrite the mass for the third object in scientific notation.\n| object | mass (g) |\n| ---- | ---- |\n| 1 | 0.0012 |\n| 2 | 35.090 |\n| 3 | 0.0000008 |\n| 4 | 6,084,000 |\n| 5 | 700.00 |\na. 8.0 x 10^-8\nb. 8.0 x 10^-6\nc. 8.0 x 10^-5\nd. 8.0 x 10^-7

question 8 of 24\nlook at the table below. rewrite the mass for the third object in scientific notation.\n| object | mass (g) |\n| ---- | ---- |\n| 1 | 0.0012 |\n| 2 | 35.090 |\n| 3 | 0.0000008 |\n| 4 | 6,084,000 |\n| 5 | 700.00 |\na. 8.0 x 10^-8\nb. 8.0 x 10^-6\nc. 8.0 x 10^-5\nd. 8.0 x 10^-7

Answer

Explanation:

Step1: Recall scientific - notation form

Scientific notation is $a\times10^{n}$, where $1\leqslant|a|\lt10$ and $n$ is an integer.

Step2: Move the decimal point

For the number $0.0000008$, move the decimal point 7 places to the right to get a number between 1 and 10. So, $a = 8.0$ and since we moved the decimal point 7 places to the right, $n=-7$.

Answer:

D. $8.0\times 10^{-7}$