refer to the above participation of state par...
refer to the above participation of state park users table. which age group had the highest percentage of its members participating in hiking?\n\na. 30 - 45\nb. 46 - 60\nc. 60+\nd. 18 - 29
Answer
# Explanation:
## Step1: Assume the columns represent different activities and we need to find the percentage for hiking. But since the table columns are not labeled, assume the last column is for hiking. Calculate percentage for each age - group.
Let's assume the total number of people in each age - group is the sum of the values in the row except the 'Total' value at the end of the row. For 18 - 29: Let the number of hikers be 21.0. Assume the total in this age - group is \(26.6 + 28.0+26.7 + 17.0-98.3=0\) (this is wrong, we need to re - assume). Let's assume the table is set up such that we calculate the percentage as \(\text{Percentage}=\frac{\text{Number of Hikers}}{\text{Total of Age - group}}\times100\).
For 18 - 29: Assume the total of 18 - 29 age - group is \(26.6\), and number of hikers is 21.0. Percentage \(P_{18 - 29}=\frac{21.0}{26.6}\times100\approx78.95\%\)
For 30 - 45: Assume total is 28.0, number of hikers is 20.7. Percentage \(P_{30 - 45}=\frac{20.7}{28.0}\times100\approx73.93\%\)
For 46 - 60: Assume total is 26.7, number of hikers is 9.3. Percentage \(P_{46 - 60}=\frac{9.3}{26.7}\times100\approx34.83\%\)
For 60+: Assume total is 5.7 + 5.9+7.1 + 2.3=21.0, number of hikers is 2.3. Percentage \(P_{60+}=\frac{2.3}{21.0}\times100\approx10.95\%\)
# Answer:
D. 18 - 29