rules for multiplying and dividing: the answer has the same number of significant figures as the quantity…

rules for multiplying and dividing: the answer has the same number of significant figures as the quantity with the fewest significant figures. example: 7.5 cm x 3.401 cm = 25.5075 cm² = 26 cm² (round to 2 sig figs) 1) 8.00 g / 5.4 ml = 2) 0.000403 m x 7.0 m = 3) 90.0000 m / 2.60x10³ s =

rules for multiplying and dividing: the answer has the same number of significant figures as the quantity with the fewest significant figures. example: 7.5 cm x 3.401 cm = 25.5075 cm² = 26 cm² (round to 2 sig figs) 1) 8.00 g / 5.4 ml = 2) 0.000403 m x 7.0 m = 3) 90.0000 m / 2.60x10³ s =

Answer

Explanation:

Step1: Identify significant - figures

For (8.00\ g/5.4\ mL), (8.00) has 3 significant figures and (5.4) has 2 significant figures.

Step2: Perform division

(8.00\div5.4=\frac{8.00}{5.4}\approx1.48148).

Step3: Round to 2 significant figures

(1.48148\approx1.5\ g/mL).

Step4: For (0.000403\ m\times7.0\ m)

(0.000403) has 3 significant figures and (7.0) has 2 significant figures.

Step5: Perform multiplication

(0.000403\times7.0 = 0.002821\ m^{2}).

Step6: Round to 2 significant figures

(0.002821\approx0.0028\ m^{2}).

Step7: For (90.0000\ m/2.60\times10^{3}\ s)

(90.0000) has 6 significant figures and (2.60\times 10^{3}) has 3 significant figures.

Step8: Perform division

(\frac{90.0000}{2.60\times 10^{3}}=\frac{90.0000}{2600}\approx0.034615\ m/s).

Step9: Round to 3 significant figures

(0.034615\approx0.0346\ m/s).

Answer:

  1. (1.5\ g/mL)
  2. (0.0028\ m^{2})
  3. (0.0346\ m/s)