a scientist uses a submarine to study ocean life. she begins 197 feet below sea level. after traveling down…
a scientist uses a submarine to study ocean life. she begins 197 feet below sea level. after traveling down for 2 seconds, shes 317 feet below sea level. find the rate of change in the submarines elevation in feet per second. if necessary, round your answer to the nearest tenth.
Answer
Explanation:
Step1: Calculate the change in elevation
The initial elevation is 197 feet below sea - level and the final elevation is 317 feet below sea - level. The change in elevation $\Delta h$ is $317 - 197=120$ feet.
Step2: Calculate the time interval
The time interval $\Delta t$ is 2 seconds.
Step3: Calculate the rate of change
The rate of change (average velocity) $v$ of the elevation is given by the formula $v=\frac{\Delta h}{\Delta t}$. Substituting the values, we get $v = \frac{120}{2}=60$ feet per second.
Answer:
60