1. a sedimentation basin is 60 ft long and 25 ft wide. if the water depth is 12 ft, what is the volume of…

1. a sedimentation basin is 60 ft long and 25 ft wide. if the water depth is 12 ft, what is the volume of water in the tank, in gallons?\nans____\n2. a circular clarifier has a diameter of 70 ft. if the water depth is 10 ft, how many gallons of water are in the tanks?

1. a sedimentation basin is 60 ft long and 25 ft wide. if the water depth is 12 ft, what is the volume of water in the tank, in gallons?\nans____\n2. a circular clarifier has a diameter of 70 ft. if the water depth is 10 ft, how many gallons of water are in the tanks?

Answer

Explanation:

Step1: Calculate volume in cubic - feet for sedimentation basin

The sedimentation basin is a rectangular - prism. The volume formula for a rectangular - prism is $V = l\times w\times h$, where $l = 60$ ft, $w = 25$ ft, and $h = 12$ ft. $V_1=60\times25\times12 = 18000$ cubic - feet. Since 1 cubic - foot is approximately 7.48 gallons, the volume in gallons $V_{gal1}=18000\times7.48 = 134640$ gallons.

Step2: Calculate volume in cubic - feet for circular clarifier

The circular clarifier is a cylinder. The volume formula for a cylinder is $V=\pi r^{2}h$, where the diameter $d = 70$ ft, so the radius $r=\frac{d}{2}=\frac{70}{2}=35$ ft and $h = 10$ ft. $V_2=\pi\times(35)^{2}\times10=\pi\times1225\times10 = 12250\pi\approx12250\times3.14 = 38465$ cubic - feet. The volume in gallons $V_{gal2}=38465\times7.48=287728.2$ gallons.

Answer:

  1. 134640 gallons
  2. 287728.2 gallons