smithers thinks that a special juice will increase the productivity of workers. he creates two groups of 50…

smithers thinks that a special juice will increase the productivity of workers. he creates two groups of 50 workers and assigns each group the same task (in this case, theyre supposed to staple a set of papers). group a is given the special juice to drink while they work. group b is not given the special juice. after an hour, smithers counts how many stacks of papers each group has made. group a made 1,587 stacks. group b made 2,113 stacks. identify the - 1. control group 2. manipulated (independent) variable 3. responding (dependent) variable 4. what should smithers conclusion be? 5. how could this experiment be improved upon?
Answer
Explanation:
Step1: Identify control group
The group without special - juice is the control group. So Group B is the control group.
Step2: Identify independent variable
The factor being changed is the special juice. So the special juice is the independent variable.
Step3: Identify dependent variable
The outcome being measured is the number of paper - stacks made. So the number of paper - stacks made is the dependent variable.
Step4: Draw conclusion
Group B (no special juice) made more paper - stacks than Group A (with special juice). So the special juice does not increase worker productivity.
Step5: Suggest improvement
Randomly assign workers to groups, increase the sample size, and conduct multiple trials.
Answer:
- Group B
- Special juice
- Number of paper - stacks made
- The special juice does not increase the productivity of workers.
- Randomly assign workers to groups, increase the sample size, and conduct multiple trials.