two gears are adjusted so that the smaller gear drives the larger one, as shown in the figure. if the…

two gears are adjusted so that the smaller gear drives the larger one, as shown in the figure. if the smaller gear rotates through an angle of 270°, through how many degrees will the larger gear rotate?

two gears are adjusted so that the smaller gear drives the larger one, as shown in the figure. if the smaller gear rotates through an angle of 270°, through how many degrees will the larger gear rotate?

Answer

Explanation:

Step1: Recall arc - length formula

The arc - length formula is $s = r\theta$, where $s$ is the arc - length, $r$ is the radius, and $\theta$ is the angle in radians. When two gears are in mesh, the arc - lengths they travel are equal. First, convert the angle of the smaller gear from degrees to radians. The angle of the smaller gear $\theta_1=270^{\circ}=270\times\frac{\pi}{180}=\frac{3\pi}{2}$ radians. Let $r_1 = 3.5$ cm be the radius of the smaller gear and $r_2 = 6.9$ cm be the radius of the larger gear. Let $\theta_2$ be the angle (in radians) of the larger gear.

Step2: Set arc - lengths equal

Since $s_1=s_2$, we have $r_1\theta_1=r_2\theta_2$. Substitute the known values: $3.5\times\frac{3\pi}{2}=6.9\times\theta_2$. Then $\theta_2=\frac{3.5\times\frac{3\pi}{2}}{6.9}=\frac{10.5\pi}{13.8}$ radians.

Step3: Convert $\theta_2$ to degrees

To convert $\theta_2$ from radians to degrees, use the conversion factor $\frac{180}{\pi}$. So $\theta_2=\frac{10.5\pi}{13.8}\times\frac{180}{\pi}=\frac{10.5\times180}{13.8}=\frac{1890}{13.8}\approx137^{\circ}$

Answer:

$137^{\circ}$