a water desalination plant can produce 2.8×10^6 gallons of water in one day. how many gallons can it produce…

a water desalination plant can produce 2.8×10^6 gallons of water in one day. how many gallons can it produce in 8 days? write your answer in scientific notation.

a water desalination plant can produce 2.8×10^6 gallons of water in one day. how many gallons can it produce in 8 days? write your answer in scientific notation.

Answer

Explanation:

Step1: Identify the daily - production and number of days

The daily production is $2.8\times 10^{6}$ gallons and the number of days is 8.

Step2: Calculate the total production

We multiply the daily production by the number of days. So, $(2.8\times 10^{6})\times8=(2.8\times8)\times10^{6}$. $2.8\times8 = 22.4$, and the result is $22.4\times 10^{6}$.

Step3: Convert to proper scientific notation

In scientific notation, the coefficient should be between 1 and 10. So, $22.4\times 10^{6}=2.24\times 10^{7}$.

Answer:

$2.24\times 10^{7}$