a water desalination plant can produce 2.6×10^6 gallons of water in one day. how many gallons can it produce…

Explanation:

Step1: Identify the daily - production and number of days

The daily production is $2.6\times 10^{6}$ gallons and the number of days is 9.

Step2: Calculate the total production

We multiply the daily production by the number of days. So, the total production $P=(2.6\times 10^{6})\times9$. Using the associative property of multiplication, $P=(2.6\times9)\times 10^{6}$. $2.6\times9 = 23.4$. So, $P = 23.4\times10^{6}$. But in scientific - notation, the coefficient should be between 1 and 10. We rewrite $23.4\times10^{6}$ as $2.34\times10^{7}$ (since $23.4=2.34\times10^{1}$ and $2.34\times10^{1}\times10^{6}=2.34\times10^{1 + 6}=2.34\times10^{7}$).

Answer:

$2.34\times 10^{7}$ gallons