calculating electric potential energy\na char...
calculating electric potential energy\na charge of 4.5×10⁻⁵ c is placed in an electric field with a strength of 2.0×10⁴ n/c. if the charge is 0.030 m from the source of the electric field, what is the electric potential energy of the charge?\nj
Answer
# Explanation:
## Step1: Recall the formula for electric potential energy
The formula for electric - potential energy $U = qEd$, where $q$ is the charge, $E$ is the electric - field strength, and $d$ is the distance from the source of the electric field.
## Step2: Identify the given values
$q = 4.5\times10^{-5}\text{ C}$, $E = 2.0\times10^{4}\frac{\text{N}}{\text{C}}$, and $d = 0.030\text{ m}$.
## Step3: Substitute the values into the formula
$U=(4.5\times 10^{-5}\text{ C})\times(2.0\times 10^{4}\frac{\text{N}}{\text{C}})\times(0.030\text{ m})$.
First, multiply the numerical values: $4.5\times2.0\times0.030 = 4.5\times0.060=0.27$.
Then, multiply the powers of 10: $10^{-5}\times10^{4}=10^{-5 + 4}=10^{-1}$.
So, $U = 0.27\times10^{-1}\text{ J}=0.027\text{ J}$.
# Answer:
$0.027$