what is the change in heat of a 3.25 - kilogr...
what is the change in heat of a 3.25 - kilogram block of aluminum when its temperature decreases from -1.0°c to -15.5°c? the specific heat of aluminum is 0.897 j/g°c. round your answer to the correct number of significant figures. joules complete the sentence. this process is because heat is by the aluminum as it cools.
Answer
# Explanation:
## Step1: Convert mass to grams
$m = 3.25\ kg\times1000\ g/kg=3250\ g$
## Step2: Calculate temperature change
$\Delta T=T_{final}-T_{initial}=- 15.5^{\circ}C-(-1.0^{\circ}C)=-14.5^{\circ}C$
## Step3: Use heat - change formula
The formula for heat change is $Q = mc\Delta T$, where $m$ is mass, $c$ is specific heat, and $\Delta T$ is temperature change.
$Q=(3250\ g)\times(0.897\ J/g^{\circ}C)\times(-14.5^{\circ}C)$
$Q = 3250\times0.897\times(- 14.5)\ J$
$Q=-41939.625\ J\approx - 41900\ J$ (rounded to 3 significant figures)
The process is exothermic because heat is released by the aluminum as it cools.
# Answer:
-41900; exothermic; released