when a constant force is applied to an object...
when a constant force is applied to an object, the acceleration of the object varies inversely with its mass. when a certain constant force acts upon an object with mass 4 kg, the acceleration of the object is 11 m/s². when the same force acts upon another object, its acceleration is 2 m/s². what is the mass of this object?
Answer
# Explanation:
## Step1: Establish the inverse - variation formula
Since acceleration $a$ varies inversely with mass $m$, we have $a=\frac{k}{m}$, where $k$ is the constant of variation (which represents the force in this context). When $m = 4$ kg and $a=11$ m/s², we can find $k$. Substitute into the formula: $11=\frac{k}{4}$, so $k = 11\times4=44$.
## Step2: Use the value of $k$ to find the new mass
We know $k = 44$ and the new acceleration $a = 2$ m/s². Substitute into the formula $a=\frac{k}{m}$, getting $2=\frac{44}{m}$. Cross - multiply: $2m=44$. Then solve for $m$: $m=\frac{44}{2}=22$ kg.
# Answer:
22