4. an object with a mass of 6.0 kg accelerate...

4. an object with a mass of 6.0 kg accelerates 4.0 m/s² when an unknown force is applied to it. what is the amount of the force? 5. an object with a mass of 7.5 kg accelerates 8.3 m/s² when an unknown force is applied to it. what is the amount of the force? 6. an object with a mass of 2000 g accelerates 8.3 m/s² when an unknown force is applied to it. what is the amount of the force? in the second set of problems below, you will be given the force applied to an object and the acceleration of that object, and then will need to solve for mass, using the equation m = f/a. in other words, you will need to divide the force by the acceleration to calculate the mass. show your work in the space provided. be sure to state the proper units in your answer, and state each answer to the nearest tenth of a unit, to match the accuracy of the measurements. 7. an object accelerates 3.0 m/s² when a force of 6.0 newtons is applied to it. what is the mass of the object? 8. an object accelerates 12.0 m/s² when a force of 6.0 newtons is applied to it. what is the mass of the object? 9. an object accelerates 5.0 m/s² when a force of 20.0 newtons is applied to it. what is the mass of the object? 10. an object accelerates 2.0 m/s² when a force of 12.0 newtons is applied to it. what is the mass of the object? 11. an object accelerates 7.2 m/s² when a force of 4.0 newtons is applied to it. what is the mass of the object? 12. an object accelerates 16.3 m/s² when a force of 4.6 newtons is applied to it. what is the mass of the object? in the third set of problems below, you will be given the force applied to an object and the mass of that object, and then will need to solve for acceleration, using the equation a = f/m. in other words, you will need to divide the force by the mass to calculate the acceleration. be sure to convert any mass stated in grams into kilograms, by dividing it by 1000 (moving the decimal place over three places to the left). for example, 1000 grams is equal to 1 kilogram. show your work in the space provided. be sure to state the proper units in your answer, and state each answer to the nearest tenth of a unit, to match the accuracy of the measurements.

Answer

# Explanation: ## Step1: Recall Newton's second - law formula $F = ma$, where $F$ is force, $m$ is mass and $a$ is acceleration. ## Step2: Solve problem 4 Given $m = 6.0\ kg$ and $a=4.0\ m/s^{2}$. Substitute into the formula: $F=6.0\times4.0 = 24.0\ N$. ## Step3: Solve problem 5 Given $m = 7.5\ kg$ and $a = 8.3\ m/s^{2}$. Substitute into the formula: $F=7.5\times8.3=62.25\approx62.3\ N$. ## Step4: Solve problem 6 First convert mass to SI unit. $m = 2000\ g=2.0\ kg$, $a = 8.3\ m/s^{2}$. Then $F=2.0\times8.3 = 16.6\ N$. ## Step5: Recall the formula for mass $m=\frac{F}{a}$ ## Step6: Solve problem 7 Given $F = 6.0\ N$ and $a = 3.0\ m/s^{2}$. Substitute into the formula: $m=\frac{6.0}{3.0}=2.0\ kg$. ## Step7: Solve problem 8 Given $F = 6.0\ N$ and $a = 12.0\ m/s^{2}$. Substitute into the formula: $m=\frac{6.0}{12.0}=0.5\ kg$. ## Step8: Solve problem 9 Given $F = 20.0\ N$ and $a = 5.0\ m/s^{2}$. Substitute into the formula: $m=\frac{20.0}{5.0}=4.0\ kg$. ## Step9: Solve problem 10 Given $F = 12.0\ N$ and $a = 2.0\ m/s^{2}$. Substitute into the formula: $m=\frac{12.0}{2.0}=6.0\ kg$. ## Step10: Solve problem 11 Given $F = 4.0\ N$ and $a = 7.2\ m/s^{2}$. Substitute into the formula: $m=\frac{4.0}{7.2}\approx0.6\ kg$. ## Step11: Solve problem 12 Given $F = 4.6\ N$ and $a = 16.3\ m/s^{2}$. Substitute into the formula: $m=\frac{4.6}{16.3}\approx0.3\ kg$. # Answer: 4. $24.0\ N$ 5. $62.3\ N$ 6. $16.6\ N$ 7. $2.0\ kg$ 8. $0.5\ kg$ 9. $4.0\ kg$ 10. $6.0\ kg$ 11. $0.6\ kg$ 12. $0.3\ kg$