a set of charged plates 0.00262 m apart have ...
a set of charged plates 0.00262 m apart have an electric field of 155 n/c between them. what is the potential difference between the plates? (unit = v)
Answer
# Explanation:
## Step1: Identify the formula
The formula for the potential - difference $V$ between two charged plates is $V = Ed$, where $E$ is the electric field and $d$ is the distance between the plates.
## Step2: Substitute the given values
We are given that $E = 155\ N/C$ and $d=0.00262\ m$. Substituting these values into the formula, we get $V=(155\ N/C)\times(0.00262\ m)$.
## Step3: Calculate the result
$V = 155\times0.00262= 0.4061\ V$.
# Answer:
$0.4061$