visible light travels at a speed 3.0×10^8 of ...
visible light travels at a speed 3.0×10^8 of m/s. if red light has a wavelength of 6.5×10^-7 m, what the frequency of this light?\n2.2×10^-15 hz\n2.0×10^2 hz\n3.0×10^8 hz\n4.6×10^14 hz
Answer
# Explanation:
## Step1: Recall the wave - speed formula
The formula for the speed of a wave is $v = f\lambda$, where $v$ is the speed of the wave, $f$ is the frequency, and $\lambda$ is the wavelength. We need to solve for $f$, so $f=\frac{v}{\lambda}$.
## Step2: Substitute the given values
We know that $v = 3.0\times10^{8}\ m/s$ and $\lambda=6.5\times 10^{-7}\ m$. Then $f=\frac{3.0\times 10^{8}}{6.5\times 10^{-7}}$.
## Step3: Perform the calculation
Using the rule of exponents $\frac{a^{m}}{a^{n}}=a^{m - n}$, we have $f=\frac{3.0}{6.5}\times10^{8-\left(-7\right)}=\frac{3.0}{6.5}\times10^{15}$. $\frac{3.0}{6.5}\approx0.46$, so $f\approx0.46\times 10^{15}=4.6\times 10^{14}\ Hz$.
# Answer:
D. $4.6\times 10^{14}\ Hz$