you also collect demographic information abou...

you also collect demographic information about the drivers in the survey. consider the following table, showing driver age group by type of enforcement action:\n\n| enforcement action (y) | driver age (x) | | | | totals |\n| ---- | ---- | ---- | ---- | ---- | ---- |\n| | 16 - 24 | 25 - 44 | 45 - 64 | 65 or older | |\n| ticket | 428 | 357 | 446 | 553 | 1,784 |\n| warning | 241 | 220 | 210 | 378 | 1,049 |\n| no action | 173 | 166 | 146 | 179 | 664 |\n| totals | 842 | 743 | 802 | 1,110 | 3,497 |\n\nchi square = 25.99, df = 6, p < 0.001.\n\nyou are interested in the possible association between drivers age and type of enforcement action. since this bivariate table is larger than 2 x 2, the measure phi is not appropriate. instead, you use cramérs v to assess the strength of the relationship. calculate cramérs v for this table. (note: the value of chi square is provided for you in the table.)\n\ncramérs v =

Answer

# Explanation: ## Step1: Recall Cramér's V formula $V = \sqrt{\frac{\chi^{2}}{n\times(k - 1)}}$, where $\chi^{2}$ is the chi - square value, $n$ is the total sample size, and $k$ is the smaller of the number of rows or columns in the contingency table. ## Step2: Identify values from the table We are given that $\chi^{2}=25.99$, and from the table, $n = 3497$. The contingency table has 3 rows and 4 columns, so $k = 3$. ## Step3: Substitute values into the formula $V=\sqrt{\frac{25.99}{3497\times(3 - 1)}}=\sqrt{\frac{25.99}{3497\times2}}=\sqrt{\frac{25.99}{6994}}$ ## Step4: Calculate the value $\frac{25.99}{6994}\approx0.003716$, and $\sqrt{0.003716}\approx0.061$ # Answer: $0.061$