in a study of cell phone usage and brain hemi...
in a study of cell phone usage and brain hemispheric dominance, an internet survey was e - mailed to 6962 subjects randomly selected from an online group involved with ears. there were 1339 surveys returned. use a 0.01 significance level to test the claim that the return rate is less than 20%. use the p - value method and use the normal distribution as an approximation to the binomial distribution. identify the null hypothesis and alternative hypothesis. a. h0:p>0.2 h1:p = 0.2 b. h0:p = 0.2 h1:p>0.2 c. h0:p≠0.2 h1:p = 0.2 d. h0:p = 0.2 h1:p≠0.2 e. h0:p<0.2 h1:p = 0.2 f. h0:p = 0.2 h1:p<0.2 the test statistic is z = - 1.60. (round to two decimal places as needed.) the p - value is . (round to three decimal places as needed.)
Answer
# Explanation:
## Step1: Identify the type of test
This is a left - tailed test as the alternative hypothesis is $H_1:p < 0.2$.
## Step2: Find the P - value
For a left - tailed test with test statistic $z=-1.60$, we use the standard normal distribution table. The P - value is the probability of getting a value less than $z = - 1.60$. Looking up the value in the standard normal table, $P(Z < - 1.60)=0.055$.
# Answer:
$0.055$