value: 4\nmr. emmer gave a test in his chemis...
value: 4\nmr. emmer gave a test in his chemistry class. the scores were normally distributed with a mean of 82 and a standard deviation of 4. a student is randomly chosen. what is the probability that the student scores an 88 or below? use the formula for a z - score $z=\frac{x - mu}{sigma}$ where x is the given value, $mu$ is the mean and $sigma$ is the standard deviation. then refer to the chart on page 11 of the lesson to find the probability\n a. 9332\n b. 8643\n c. 9918\n d. 6915\n#6/7
Answer
# Explanation:
## Step1: Calculate the z - score
Given $x = 88$, $\mu=82$, $\sigma = 4$. Using the z - score formula $z=\frac{x-\mu}{\sigma}$, we have $z=\frac{88 - 82}{4}=\frac{6}{4}=1.5$.
## Step2: Find the probability from the z - table
Looking up the z - score of 1.5 in the standard normal distribution table, the corresponding cumulative probability is 0.9332.
# Answer:
A. 0.9332